Qardatic equation whose zeroes are 5+√3 and 5-√3
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Answer:
Step-by-step explanation:
Zeroes are 5+root3 and 5-root3.
Therefore, sum of zeroes= 10
And product of zeroes= 25-3=22
Beacause {(a+b)(a-b)=a^2-b^2}
Now, we know a quadratic equation is of form:
K(x^2-(sum of zeroes)x+(product of zeroes)
Therefore the equation would be:
K(x^2-10x+22)
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