Math, asked by chavanlata437, 10 months ago

Qe 30. A dinner is arranged for 11 guests in which there are 4 African, 1 American and 6 Indian are invited
The 4 African wish to occupy 2 comer seats at each end and the American old man refuses to have a African
on his either side In how many ways can all guests be arranged?

Answers

Answered by wars8188018
0

Answer:

4 african can sit as they want to sit, i.e,2 comer seat at each end,and now four indians will sit two on ech side of the African of the one seat comer and the same on the second side of the seat comer with the African. Now old American will sit on one side of the Indian on the one side of seat comer and remaining two indians will sit on both the sides of the seat comer........

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