QFT: What does “finiteness” mean?
Answers
Answered by
7
As above: what is the definition of a QFT to be "finite"?
That all UV corrections are finite and there are no divergences at all?
That there are divergences, but these divergences can be absorbed in the (suppose renormalisable) Lagrangian with counterterms, leaving just a finite quantum correction?
That all UV corrections are finite and there are no divergences at all?
That there are divergences, but these divergences can be absorbed in the (suppose renormalisable) Lagrangian with counterterms, leaving just a finite quantum correction?
Answered by
8
hey ❕ I think this is your answer
As above: what is the definition of a QFT to be "finite"?
That all UV corrections are finite and there are no divergences at all?
That there are divergences, but these divergences can be absorbed in the (suppose renormalisable) Lagrangian with counterterms, leaving just a finite quantum correction?
may it helps you
As above: what is the definition of a QFT to be "finite"?
That all UV corrections are finite and there are no divergences at all?
That there are divergences, but these divergences can be absorbed in the (suppose renormalisable) Lagrangian with counterterms, leaving just a finite quantum correction?
may it helps you
Similar questions