Question

qhy horse power engine is rquired to lift 18.24 quimtql of coal per minute from a mine 50m deep? g = 10m/s​

Answer 1

Answer:

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Answer 2

Correct Question :-

What horse pwoeris required to lift 18.24 quitnals of coal per minute from a mine 50 m deep? ( g = 10 m² )

Answer :-

Given -

• Mass = 18.24 quintal = 1824 kg
• Time = 1 min = 60 sec
• Height = 50 m

To find -

• Power (P)

Solution :-

• m = 1824 kg
• t = 60 s
• h = 50 m

Substituting the value in formula :-

$\sf P = \frac{mgh}{t}$

$\sf = \frac{1824 \times 10 \times 50}{60}$

$\sf = 15200 W$

We know,

1 Horse power = 1/746

$\sf 15200 W = \frac{15200}{746}$

$\sf = 20.4 Hp$

Therefore, the engine of 20.4 horsepower is required.