Question

QI. A train accelerates from 36 km/h to 54 km/h in 10 sec Acceleration The distance travelled by car (s?)​

Answer 1

Answer:

Initial speed u = 36 km/h = 36 x 1000/3600 m/s = 10 m/s

Final speed v = 54 km/h = 54 x 1000/3600 m/s = 15 m/s

Time t = 10 s

Acceleration a = (v - u)/t = (15 - 10)/10 = 5/10 = 0.5 m/s2.

Distance travelled S = ut + ½ at2

= 10 x 10 + ½ x 0.5 x 10 x 10 m = 100 + 25

= 125 m

Explanation:

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