Question

QI. Find the coordinate which divide the line segment (6,3) and (-4,5) in the
at 3:3​

Answer 1

Answer:

Using the section formula, if a

point (x,y) divides the line joining the points (x1, yı) and (x2, y2) internally in the ratio m:n , then

mx2 + nxi my2 + nyi

(x,y) =

m+n

m+n

Substituting (x1, yı) = (6,3) and (x2, y2) = (-4,5) and m = 3, n= 2 in the section formula, we get

the point P= 3(-4) + 2(6) 3(5) + 2(3) 3 + 2

3 + 2

21 0,

5

Answer 2

$x_{1} = 6 \: \: \: \: \: \: \: \: \: \: \: y_{1} = 3 \\ x_{2} = ( - 4) \: \: \: \: \: \: \: \: \: \: \: \: y_{2} = 5 \\ \\ m_{1} = 3 \: \: \: \: \: \: \: \ m_{2} = 3$

Happiee Republic day..☺