QI7 A die is thrown.find the probability of getting
i) a multiple of 2 or 3
ii) an even prime number
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1 favorable condition are 2,3,4,6
total outcomes are 6
probability of getting a multiple of 2 or 3 =4/6 =2/3
2 favorable condition are 2
total outcomes are 6
probability of getting an even prime number =1/6
Answered by
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S = { 1 , 2, 3, 4 , 5 , 6 }
n ( S ) = 6
let A is the event of getting multiple of 2 or 3
A = { 2, 3 , 4 ,6 }
n ( A ) = 4
P ( A ) = n (A ) / n ( S )
= 4/ 6
= 2/3
let B is the event of getting an even prime no.
B = { 2 }
n ( B )= 1
P ( B ) = n( B ) / n ( S )
= 1 / 6
n ( S ) = 6
let A is the event of getting multiple of 2 or 3
A = { 2, 3 , 4 ,6 }
n ( A ) = 4
P ( A ) = n (A ) / n ( S )
= 4/ 6
= 2/3
let B is the event of getting an even prime no.
B = { 2 }
n ( B )= 1
P ( B ) = n( B ) / n ( S )
= 1 / 6
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