Question

Qid : 22 - find the perimeter (in cm) of a semicircle of radius 7 cm.

Answer 1

Perimeter of a circle = 2 × π × radius=2πr

Perimeter of semi circle= 2πr/2

= π × radius

= π × 7

$= \frac{22}{7} \times 7$

$= {22cm}^{2}$

Answer 2

Answer:-

Step-by-step explanation:

Given , radius of semicircle = 7 cm

Find the area of semicircle:

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since , we know that area of semicircle

= area of circle / 2

= πr^2 / 2 = ( 22/ 7 ) × (7)^2/ 2

22 × 7 / 2 = 77 cm^2

Find the perimeter of semicircle:

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perimeter of semicircle = circumference of semicircle + diameter of semicircle

= πr + 2r

= (22/ 7) × 7 + 2 × 7

= 22 + 14 = 36 cm

therefore, are of semicircle = 77 cm^2

perimeter of semicircle = 36 cm

Answer:area=77cm^2, perimeter=36 cm

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