Question

QII.
The boiling point of a solution of urea in water is 100.13° C. Calculate freezing point of
solution. (Kf=1.86 K kg mol!, Ky=0.52 kkg mol ).
(molar mass of urea = 60 g mol').​

Answer 1

ΔTf =kf m ( 1)

ΔTb =Kb m. ( 2)

100.13-100/Tf = 0.52 /1.86

0.13 X 1.86/0.52 =Tf = -0.465

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