Question

QIII ANSWER THE FOLLOWING QUESTIONS. (8)
(1) Complete the following table [show the calculations]
u a s v
10 m/s 2 m/s2
75m _____

Answer 1

Given that:

• Initial velocity, u = 10 mps
• Acceleration, a = 2 mps sq.
• Distance, s = 75 m

To calculate:

• Final velocity, v

Solution:

• Final velocity, v = 20 mps

Using concept:

• Third equation of motion

Using formula:

• ${\small{\underline{\boxed{\pmb{\sf{v^2 \: - u^2 \: = 2as}}}}}}$

Required solution:

$\longmapsto \sf v^2 \: - u^2 \: = 2as \\ \\ \longmapsto \sf v^2 - (10)^{2} = 2(2)(75) \\ \\ \longmapsto \sf v^2 - 100 = 4(75) \\ \\ \longmapsto \sf v^2 - 100 = 300 \\ \\ \longmapsto \sf v^2 = 300 + 100 \\ \\ \longmapsto \sf v^2 = 400 \\ \\ \longmapsto \sf v \: = \sqrt{400} \\ \\ \longmapsto \sf v \: = 20 \: mps$

Answer 2

Correct Question :-

✠ Complete the Following Table :-

• U = 10 m/s
• A = 2 m/s²
• S = 75 m .
• V = ?

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Answer :-

• Final Velocity [ V ] = 20 m/s .

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Explanation :-

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∓ Here, Initial Velocity is given 10 m/s. Acceleration is given 2 m/s² . Distance is given 75 meter . And, we have to find the Final Velocity .

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• Now, let's solve step by step ------

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◆ Formula Required :-

• v² - u² = 2 ᴀs

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◆ Here ,

• v denotes to Final Velocity
• u denotes to Initial Velocity
• ᴀ denotes to Acceleration
• s denotes to Distance

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∴ By substituting the given values :-

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$\dashrightarrow \: \sf{ {v}^{2} - {10}^{2} = 2 \times (2) \: (75) } \\ \\ \dashrightarrow \: \sf{ {v}^{2} - 100 =(4) \: (75) } \\ \\ \dashrightarrow \: \sf{ {v}^{2} - 100 = 300} \\ \\ \dashrightarrow \: \sf{ {v}^{2} = 300 + 100 } \\ \\ \dashrightarrow \: \sf{ {v}^{2} =400 } \\ \\ \dashrightarrow \: \sf{ v = \sqrt{400} } \\ \\ \dashrightarrow \: \sf{v = 20}$

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Hence :-

• Final Velocity [ V ] = 20 m/s .

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Learn More :-

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$\begin{gathered}\begin{gathered}\boxed{\begin{array}{c}\\ {\pmb{\sf\bigstar\: \: {Three \: equations\: of \: motion}}} \\ \\ \sf 1.] \:\: v \: = u \: + ᴀt \\ \\ \sf 2.]\:\: s \: = ut + \: \dfrac{1}{2} \: ᴀt^2 \\ \\ \sf 3.] \:\: v^2 - u^2 \: = 2ᴀs\end{array}}\end{gathered}\end{gathered}$

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