Math, asked by sshalem523, 10 hours ago

qkwyhcywzh please answer me


Kamala has a triangular field PQR. She wanted to grow potatoes and onions in it. For that, she divided the field in to two parts by joining the midpoint of the longest side to the opposite vertex as shown in the figure. Find the area used for growing potatoes in hectares ( 1 hectare = 10000 m²) ATE S 600 m​​

Answers

Answered by shrijithsairam
1

Answer:

Step-by-step explanation:

You have studied in earlier classes about figures of different shapes such as squares,

rectangles, triangles and quadrilaterals. You have also calculated perimeters and the

are hoe is the is the do fihtobr i iumh how

Answered by adharrshv478
3

Answer:

192

Step-by-step explanation:

E is the midpoint of AD, then

AE=ED=200m

Area of wheat field =ar△ABC

Area of potato field =ar△AEC

Area of onion field =ar△EDC

ar△ABC =

S(S−a)(S−b)(S−c)

,S=

2

200+240+360

=400m

=

400(400−200)(400−240)(400−360)

=

400×200×160×40

=16000

2

m

2

=1.6

2

hectare

=1.6×1.414=2.26hectares

In △ACD

△AEC and △CED have same base [arAE=ED=200m]

and they have same height CF

Therefore, ar△AEC=ar△CED=

2

1

ar△ACD

ar△ACD =

S(S−a)(S−b)(S−c)

,S=

2

240+320+400

=480m

=

480(480−240)(480−320)(480−400)

=

480×240×160×80

=38400m

2

=3.84hectares

∴ar△AEC=ar△CED=

2

1

×3.84=1.92hectares

Therefore,

Area of wheat field =2.26hectares

Area of potato field =1.92hectares

Area of onion field =1.92hectares

For potato 100m=100×1.92=192hectares

Attachments:
Similar questions