Question

Ql. Find the zeroes of the following quadratic polynomials and verify the relationship

between the zeroes and their coefficients:

(i) 6x2 - 3 - 7x

(ii) t2 -15​

Answer 1

Answer:

Polynomial 1 : 6x² - 3 - 7x

• 6x² - 7x - 3
• 6x² - 9x + 2x - 3
• 3x ( 2x - 3 ) + 1 ( 2x - 3 )
• ( 3x + 1 ) ( 2x - 3 )
• 3x + 1 = 0 And 2x - 3 = 0
• x = -1/3 And x = 3/2

Therefore zeroes of p(x) are (-1/3) and 3/2

Verification

Verification Here

• a = 6
• b = (-7)
• c = (-3)

Sum of zeroes = -b/a

• (-1/3) + 3/2 = -(-7/6)
• [-1(2) + 3(3) ] / 6 = 7/6
• (-2+9) / 6 = 7/6
• 7/6 = 7/6

Product of zeroes = c/a

• (-1/3) x 3/2 = (-3/6)
• (-1/2) = (-1/2)

Hence verified

Answer 2

Answer:

Answer : (-1/3) and 3/2

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