Question

Qn3 In the above figure M is the centre of the circle AB and CD are two chords . If MQ + CD,MP perpendicular to AB AB =24 cm and MP= 9 cm 1. Find the radius of the circle ? 2. If MQ=12 cm ,find the length of CQ ? 3. What is the length of the chord CD? (3) ​

Answer 1

Answer:

10 cm

Step-by-step explanation:

Given: AB=24 cm;ON=5 cm,OM=12 cm.

∵ON⊥AB

N is the mid point of AB.

∴AN= 24/2 cm =12 cm

Now from △ANO,

AO sq +ONsq+ANsq  

      (∵AO=CO=r)

⇒r sq = 5 sq +12 sq  

=  r  = 25+144

= r = 13

From ΔCMO,

CM sq = COsq - OMsq

CM sq =13 sq - 12sq

CM sq =169 - 144

CM sq =25

CM=5

CD=2 CM=2×5 cm=10 cm