Question

qnd this question in breaf ​

Answer 1

Since RS is a straight line.

4b+75°+b=180°. [Linear pair]

5b=105°

b=21°

Since PQ is a straight line.

75°+21°+a=180°. [Linear pair]

96°+a=180°

a=84°

Since RS is a straight line.

2c+a=180°. [Linear pair]

2c+84°=180°

2c=96°

c=48°

Now pls mark me the brainliest

Answer 2

Hii..

Here's your answer..

According to the given figure..

Given = Angle POT = 75°.

Find = Angle a, b, & c.

Solution :- ∠ POR + ∠ POT + ∠ TOS = 180° (Linear pair angles)

Now applying A.S.P of a ∆ , we get

4b + 75° + b = 180°

5b = 75° = 180°

5b = 180° - 75°

5b = 105°

b = 21°

And, ∠ POR = 4b = 4 (21)

∠ POR = 84°

And,

∠ SOQ = ∠ POR   (vertically opposite angles)

Substitute the values, we get

a = 84°

And,

∠ QOR = ∠ POS (vertically opposite angles)

Substitute the values, we get

2c = 75° + 21°

2c = 96°

c = 96/2

c = 48°

So,

a = 84°

b = 21°

c = 48°

Hope this is helpful for you.

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