Question

qno34..answer of these​

Answer 1

$\rm{(3^{5} \times 5^{2} \times 3^{2})/(6^{2} \times \sqrt{25} \times \sqrt{49})=(3^{5} \times 5^{2} \times 3^{2})/(6^{2} \times 5 \times 7)}$

$\longrightarrow\rm{(3^{5} \times 5^{2} \times 3^{2})/(6^{2} \times \sqrt{25} \times \sqrt{49})=(3^{5+2} \times 5^{2})/(6^{2} \times 5 \times 7)}$

$\longrightarrow\rm{(3^{5} \times 5^{2} \times 3^{2})/(6^{2} \times \sqrt{25} \times \sqrt{49})=(3^{7} \times 5)/(6^{2} \times 7)}$

$\longrightarrow\rm{(3^{5} \times 5^{2} \times 3^{2})/(6^{2} \times \sqrt{25} \times \sqrt{49})=(3^{7} \times 5)/(36 \times 7)}$

$\longrightarrow\rm{(3^{5} \times 5^{2} \times 3^{2})/(6^{2} \times \sqrt{25} \times \sqrt{49})=(2187 \times 5)/252}$

$\longrightarrow\rm{(3^{5} \times 5^{2} \times 3^{2})/(6^{2} \times \sqrt{25} \times \sqrt{49})=10935/252=1215/28}$