Qno9- find the value of m so that (2x-3) is a factor of 6x^3-x^2-10x+m
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6x³-x²-10x+m=0
2x-3=0
x=3/2
6(3/2)³-(3/2)²-10(3/2)+m=0
6×27/8-9/4-15+m=0
3×27/4-9/4-15+m=0
81/4-9/4-15+m=0
(81-9-60+4m)/4=0
81-9-60+4m=0
72-60+4m=0
12+4m=0
4m=-12
m=-12/4
m=-3
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