Question

Qns. 12
calculate the uncertainity in d velocity of an
electron if d uncertainity in d position is
100pm​

Answer 1

Answer:

According to Heisenberg's uncertainity principle:

Δx.Δp=

4π

h

Δx.Δ(mv)=

4π

h

Δv=

4πmΔx

h

h=6.626×10

−34

Js=Planck's constant

Given m=mass of electron=9.1×10

−31

kg and Δx=1000

A

˚

=10

−7

m

upon substitution we get:

Δv=

4×3.14×9.1×10

−31

×10

−7

6.626×10

−34

Δv=0.0579×10

4

=5.79×10

2

m/s

Answer 2

Answer:

According to Heisenberg's uncertainity principle:

Δx.Δp=  

4π

h

​  

 

Δx.Δ(mv)=  

4π

h

​  

 

Δv=  

4πmΔx

h

​  

 

h=6.626×10  

−34

Js=Planck's constant

Given m=mass of electron=9.1×10  

−31

 kg and Δx=1000  

A

˚

=10  

−7

m

upon substitution we get:

Δv=  

4×3.14×9.1×10  

−31

×10  

−7

 

6.626×10  

−34

 

​  

 

Δv=0.0579×10  

4

=5.79×10  

2

m/s

Explanation: