(qp-1)x + 3y=5 and 3x +(q-1)y=2 fond the value of p and q which the system of equation has infinite many solutions
Answers
Step-by-step explanation:
9 Solutions. All Rs Aggarwal 2019 Solutions for class Class 10 Math are prepared by experts and are 100% accurate.
Page No 87:
Question 1:
2x+3y=2,x-2y=8.
ANSWER:
On a graph paper, draw a horizontal line X'OX and a vertical line YOY' representing the x-axis and y-axis, respectively.
Graph of 2x + 3y = 2
2x + 3y = 2
⇒ 3y = (2 − 2x)
⇒ 3y = 2(1 − x)
⇒ y =
2(1-x)
3
...(i)
Putting x = 1, we get y = 0
Putting x = − 2, we get y = 2
Putting x = 4, we get y = −2
Thus, we have the following table for the equation 2x + 3y = 2.
x 1 −2 4
y 0 2 −2
Now, plot the points A(1, 0), B(− 2 , 2) and C(4, − 2) on the graph paper.
Join AB and AC to get the graph line BC. Extend it on both ways.
Thus, the line BC is the graph of 2x + 3y = 2.
Graph of x − 2y = 8
x − 2y = 8
⇒ 2y = ( x − 8)
⇒ y=
x-8
2
...(ii)
Putting x = 2, we get y = −3
Putting x = 4, we get y = −2
Putting x = 0, we get y = −4
Thus, we have the AB and AC to get the graph line BC. Extend it on both ways.
Thus, the line BC is the graph of 2x + 3y = 2.
Graph of x − 2y = 8
x − 2y = 8
⇒ 2y = ( x − 8)
⇒ y=
x-8
2
...(ii)
Putting x = 2, we get y = −3
Putting x = 4, we get y = −2
Putting x = 0, we get y = −4
Thus, we have the following table for the equation x - 2y = 8.
x 2 4 0
y − 3 − 2 − 4
Now, plot the points P(0, − 4) and Q(2, − 3). The point C(4, −2) has already been plotted. Join PQ and QC and extend it on both ways.
Thus, line PC is the graph of x − 2y = 8.
Answer:
3/q-1=5/2
6=5q-5
11/5=q
11×p-1/3×5=3×5/6
11×p-1/6=0
11xp-1=0
11×p=1
p=1/11