Math, asked by atul2648, 11 months ago

QP II TS and angle QRS = 36°. Then find the value of angle PQR/12°.

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Answered by Anonymous

8

Solution ✌️✌️

<CEF=180°-2x°

<BEF=<CEF+36°

=180°-2x°+36°=216°-2x°

now...

216°-2x°=x°

=>3x°=216

=>x°=72°

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