QP is a tangent to a circle with centre O at a point P on the circle. lf ∆OPQ is isosceles, then angal OQP equals.
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Answer:
Because angle opq is a right angle (Radius is perpendicular at tangent point)
It is isosceles right triangle
And angle OQP equals 45 degree
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pq is tangent and Oq is radius
we know that tangent is perpendiculatr to radius
Angle Opq = 90°
Angle OPQ is isoceles
- OP = PQ
Angle OQP = Angle POQ
SO,
angle Oqp = 1/2 X 90°
= 45°
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