Question

QQ.A wood sample weighs 90g and 50g before and after seasoning. Calculate the percentage moisture content of the wood

Answer 1

Step-by-step explanation:

Given:

A wood sample weighs 90 g and 50 g before and after seasoning. Calculate the percentage moisture content of the wood?

To find:

Calculate the percentage moisture content of the wood

Solution:

Seasoning of wood: The process of removing the bound moisture in the walls of the wood cells is called seasoning of wood.

The weight of wood before seasoning = 90 g

The weight of the wood after seasoning = 50 g

We know,

$\begin{gathered}\boxed{\bold{Moisture\:content \:(wet \:basis)= \frac{w - d}{w} \times 100}}\\\\\boxed{\bold{Moisture\:content \:(dry \:basis)= \frac{w - d}{d} \times 100}}\end{gathered}$

where w = wet weight and d = dry weight

Therefore,

Percentage Moisture Content (wet basis) of the wood:

$= \frac{90 - 50}{90} \times 100$

$= \frac{40}{90} \times 100$

$= \boxed{\bold{44.44\%}}$

Percentage Moisture Content (dry basis) of the wood:

$= \frac{90 - 50}{50} \times 100$

$= \frac{40}{50} \times 100$

$= \boxed{\bold{80\%}}$

-----------------------------------------------------------------------------------------