QR/QS=QT/PRAND ANGLE 1 = ANGLE 2 sow that ∆PQS~TQR
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Answered by
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Answer:
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Step-by-step explanation:
Answered by
5
Step-by-step explanation:
Given:
∠1 = ∠2
To Prove:
ΔPQS ~ ΔTQR
Proof:
Given, ∠1 = ∠2
=> PR = QP ---(i) ( sides opposite to equal angles are equal)
Given,
Putting Eq (i) ,
---------------(ii)
in ΔPQS and ΔTQR
∠PQS = ∠TQR ( common )
( from (ii) )
∴ ∆PQS ~ ΔTQR ( SAS similarity )
Hence Proved . (ANS.)
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