Math, asked by 307116, 6 months ago

QR/QS=QT/PRAND ANGLE 1 = ANGLE 2 sow that ∆PQS~TQR​

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Answers

Answered by Anonymous
1

Answer:

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Step-by-step explanation:

Answered by Nihar1729
5

Step-by-step explanation:

Given:

          \frac{QR}{RS} = \frac{QT}{PR}  

            ∠1 = ∠2

To Prove:

              ΔPQS ~ ΔTQR

Proof:

         Given, ∠1 = ∠2

              => PR = QP   ---(i)    ( sides opposite to equal angles are equal)

         Given,

                  \frac{QR}{RS} = \frac{QT}{PR}  

                Putting Eq (i) ,

                     \frac{QR}{RS} = \frac{QT}{QP}     ---------------(ii)

    in ΔPQS and ΔTQR

             ∠PQS = ∠TQR ( common )

              \frac{QR}{RS} = \frac{QT}{QP}      ( from (ii) )

              ∴ ∆PQS ~ ΔTQR​      ( SAS similarity )

                      Hence Proved . (ANS.)

                               Hope it helps

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