Question

QR/QS=QT/PRAND ANGLE 1 = ANGLE 2 sow that ∆PQS~TQR​

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Step-by-step explanation:

Given:

          $\frac{QR}{RS} = \frac{QT}{PR}$  

            ∠1 = ∠2

To Prove:

              ΔPQS ~ ΔTQR

Proof:

         Given, ∠1 = ∠2

              => PR = QP   ---(i)    ( sides opposite to equal angles are equal)

         Given,

                  $\frac{QR}{RS} = \frac{QT}{PR}$  

                Putting Eq (i) ,

                     $\frac{QR}{RS} = \frac{QT}{QP}$     ---------------(ii)

    in ΔPQS and ΔTQR

             ∠PQS = ∠TQR ( common )

              $\frac{QR}{RS} = \frac{QT}{QP}$      ( from (ii) )

              ∴ ∆PQS ~ ΔTQR​      ( SAS similarity )

                      Hence Proved . (ANS.)

                               Hope it helps

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