Qs 4 (1) - i]
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Answer:
x² + 8x + 12 = 0
Step-by-step explanation:
Difference between the roots of a quadratic equation is 4.
α - β = 4 --- (i)
Difference between the cubes of those roots is 208
α³ - β³ = 208 ---- (ii)
On cubing (i), we get
(α - β)³ = 4³
⇒ α³ - β³ - 3αβ(α - β) = 64
⇒ 208 - 3αβ(4) = 64
⇒ αβ = 12
Once again Squaring (i), we get
(α - β)² = 4²
⇒ α² + β² + 2αβ = 16
⇒ α² + β² + 2(12) = 16
⇒ α² + β² = 40
[∴(a + b)² = a² + b² + 2ab]
⇒ (α + β)² = α² + β² + 2αβ
⇒ (α + β)² = 40 + 2(12)
⇒ α + β = 8
The sum of the zeros is 8.
The quadratic equation form is :
x² + (a + b)x + ab = 0
⇒ x² + 8x + 12 = 0
Therefore,
Required Equation = x² + 8x + 12 = 0
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