qs 55 please from circles
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line from center of circle is always perpendicular to chord
therefore CD pass from center of circle because it is perpendicular to AB
therefore CD is diameter
arc CXA+arc DYA +arc DZB+arc CWB =semi circle CXAYD +semicircle CWBZD
therefore CD pass from center of circle because it is perpendicular to AB
therefore CD is diameter
arc CXA+arc DYA +arc DZB+arc CWB =semi circle CXAYD +semicircle CWBZD
abhisar1:
but it has to be perpendicular bisector to pass through the centre
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