Question

QS. Find the velocity of bullet of mass 5 gram which is fired from a pistol of mass 1.5 kg. The recoil velocity of pistol
is 1.5 m/s.​

Answer 1

Answer:

Mass1= 5g=0.05kg

Mass2=1.5kg

u1 and u2 = 0

v1=1.5m/s.

=(0.05+1.5)kg ×0m s-1

=0kg ms-1

=1.5kg×vms-1

=(3+0.05v)kg m s-1

=3.05kgms

=3+0.05v=0

=v=0.1666... ms-1