Qs is the diameter ,o is the. Centre of the circle.APT is a tangent at P .find angle APQ
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Given : QS is the diameter and O is the centre of the circle APT is the tangent at P
PQS=30° , QSR=60°
To Find : angle APQ
Solution:
Join OP
in ΔQOP
OP = OQ = Radius as O is center
=> ∠OQP = ∠OPQ
∠OQP = 30°
=> ∠OPQ = 30°
∠APO = ∠APQ + ∠OPQ
∠APO = 90° as APT is tangent
=> 90° = ∠APQ + 30°
=> ∠APQ = 60°
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