Question

нεяε ¡ร тнε quεรт¡σห ✌

_______________

11x+15y+23=0;7x-2
⬆️solve x and y

_______________​

Answer 1

Answer:

$x = .28 \\ y = 1.7$

Step-by-step explanation:

Given:-

$11x + 15y + 23 = 0 \\ 7x - 2 = 0$

find the value of x,

$7x = 2 \\ x = \frac{2}{7} = 0.28$

put in the above equation to find y,

$= > 11( \frac{2}{7} ) + 15y + 23 = 0 \\ = > \frac{22}{7 } + 15y + 23 = 0 \\ = > \frac{22 + 161}{7} + 15y = 0 \\ = > \frac{183}{7 } + 15y = 0 \\ = > 15y = \frac{183}{7} \\ = > y = \frac{18 3}{7 \times 15} \\ = > y = \frac{183}{105} = 1.7$

Hope it helps you

Yo❤️

@AR+NAV❤️

Answer 2

Answer:

Answer:-

$\begin{lgathered}x = .28 \\ y = 1.7\end{lgathered}$

Step-by-step explanation: to

• Given:-

$\begin{lgathered}11x + 15y + 23 = 0 \\ 7x - 2 = 0\end{lgathered}$

• find the value of x,

$\begin{lgathered}7x = 2 \\ x = \frac{2}{7} = 0.28\end{lgathered}$

• put in the above equation to find y,

$\begin{lgathered}= > 11( \frac{2}{7} ) + 15y + 23 = 0 \\ = > \frac{22}{7 } + 15y + 23 = 0 \\ = > \frac{22 + 161}{7} + 15y = 0 \\ = > \frac{183}{7 } + 15y = 0 \\ = > 15y = \frac{183}{7} \\ = > y = \frac{18 3}{7 \times 15} \\ = > y = \frac{183}{105} = 1.7\end{lgathered}$

Hope it helps you

Yo❤️