quadarticpolynomial and verify the relationship between the zeroand the cofficient 6x-3-7x
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6x2 – 3 – 7x
Factorize the equation
Compare the equation with ax2 + bx + c = 0
We geta = 6 ,b=-7 c= -3
To factorize the value we have to find two value which sum is equal to b =-7
product is a*c = 6*-3=-182 and -9 are required values which sum is 2 – 9 = - 7
product is 2 * - 9= - 18
So we can write middle term as -7x = 2x – 9x
We get 2x (3x +1) -3(3x +1) = 0(3x+1)(2x-3) = 03x+1 = 0 , 2x-3 = 0
Solve for first zero3x = - 1x = -1/3
Solve for second zero2x-3 = 02x = 3X = 3/2
Plug the values of a , b and c we get
Sum of zeros -b/a = -(-7/6)= 7/6
Product of zero c/a = -3/6= -1/2
hence we have verified the relationship
Factorize the equation
Compare the equation with ax2 + bx + c = 0
We geta = 6 ,b=-7 c= -3
To factorize the value we have to find two value which sum is equal to b =-7
product is a*c = 6*-3=-182 and -9 are required values which sum is 2 – 9 = - 7
product is 2 * - 9= - 18
So we can write middle term as -7x = 2x – 9x
We get 2x (3x +1) -3(3x +1) = 0(3x+1)(2x-3) = 03x+1 = 0 , 2x-3 = 0
Solve for first zero3x = - 1x = -1/3
Solve for second zero2x-3 = 02x = 3X = 3/2
Plug the values of a , b and c we get
Sum of zeros -b/a = -(-7/6)= 7/6
Product of zero c/a = -3/6= -1/2
hence we have verified the relationship
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