Question

Quadratic equation
2x^{2} -5x-3=0

Answer 1

Answer:

$x = 3 \: \: or \: - \frac{1}{2}$

Step-by-step explanation:

$2 {x}^{2} - 5x - 3 = 0 \\ 2 {x}^{2} - 6x + x - 3 = 0 \\ 2x(x - 3) + 1(x - 3) = 0 \\ (2x + 1)(x - 3) = 0 \\ 2x + 1 = 0 \: \: or \: \: x - 3 = 0 \\ x = - \frac{1}{2} \: \: or \: \: x = 3$

Hope it helps you.

Answer 2

Answer:

Here's your answer friend.

Step-by-step explanation:

First-

Write -5x as a difference

$2x {}^{2} + x - 6x - 3 = 0$

factor out x from the expression

$x(2x + 1) - 6x - 3 = 0$

factor out -3 from the expression

$x(2x - 1) - 3(2x - 1) = 0$

separate into possible cases

$(2x + 1)(x - 3)$

this equation has two solutions

$x = \frac{ - 1}{2} \\ x = 3$

thanks

that's your answer friend.

Hope it helps.

please mark my answer as the brainliest