Question

quadratic equation (2x+3) (3x-2)+2=0​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

Given :

To solve for x , if

(2x+3) (3x-2)+2=0​

Solution :

⇒ (2x+3) (3x-2)+2=0​

⇒ 6x² + 5x - 6 + 2 = 0

⇒ 6x² + 5x - 4 = 0

⇒ 6x² + 8x - 3x - 4 = 0

⇒ 2x(3x + 4) - 1(3x + 4) = 0

⇒ (2x - 1)(3x + 4) = 0

For product of two numbers to be 0, either (or) both of the factors must be equal to 0,.

⇒ (2x - 1) = 0 (or) (3x + 4) = 0

⇒ 2x - 1 = 0 (or) 3x + 4 = 0

⇒ 2x = 1 (or) 3x = - 4

⇒ $x = \frac{1}{2}$ (or) $x = \frac{-4}{3}$