Question

quadratic equation 2x2+px-4=0 a root is 2 find the value of p​

Answer 1

Step-by-step explanation:

Value of p = -6,

and

Other root = 1

Step-by-step explanation:

Given quadratic equation

2x²+px+4 = 0 ---(1)

and

One root (m) = 2 /* given

Let the second root = n

i ) Substitute m=2 in equation (1), we get

2(2)²+p×2 +4 =0

=> 8+2p+4=0

=> 12+2p=0

=> 2p = -12

Divide each term by 2, we get

=> p = -6

ii ) Now,

Compare 2x²+px+4 =0 with

ax²+bx+c=0, we get

a = 2 , b = p , c = 4

Sum\: of\: the\: roots =\frac{-b}{a}Sumoftheroots=a−b

\implies m+n=\frac{-(-6)}{2}⟹m+n=2−(−6)

\implies 2+n=\frac{6}{2}⟹2+n=26

\implies 2+n=3⟹2+n=3

\implies n=3-2⟹n=3−2

\implies n=1⟹n=1

Therefore,

Value of p = -6

and

Other root = 1

Answer 2

Answer:

2x2+px-4=0

4+p(2)-4=0

        p(2)=0

          p=0

Step-by-step explanation: