quadratic equation 3/2x^2-5=0
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We have,
2x
2
−5x+3=0
⇒x
2
−
2
5
x+
2
3
=0 (Dividing throughough by 2)
⇒x
2
−
2
5
x=−
2
3
(Shifting the constant term on RHS)
⇒x
2
−2(
4
5
)x+(
4
5
)
2
=(
4
5
)
2
−
2
3
(Adding (
2
1
Coeff.ofx)
2
onboth sides)
⇒(x−
4
5
)
2
=
16
25
−
2
3
⇒(x−
4
5
)
2
=
16
1
⇒x−
4
5
=±
4
1
⇒x=
4
5
±
4
1
⇒x=
4
5
+
4
1
=
4
6
orx=
4
5
−
4
1
=
4
4
⇒x=
2
3
orx=1
Here the roots of the equation are
2
3
and 1 hii please follow me back
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