Question

quadratic equation:
√(8x²-12x+29)=3x-2

Answer 1

Step-by-step explanation:

$\sqrt{(8x^{2} -12x+29)} =3x-2$

Squaring both sides

$(8x^{2} -12x+29)=$ $(3x-2)^{2}$

$8x^{2} -12x+29=9x^{2} -12x+4$

$x^{2} -25 = 0$

$x^{2} = 25$

$x$ = ± $\sqrt{25}$

$x$ = ±5

∴ The roots of the equation are + 5 and -5.

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