Question

Quadratic equation 9x^2-24x+16=0

Answer 1

$a = 9 \\ b = - 24 \\ c = 16 \\ \sqrt{ {b}^{2} - 4ac} \\ = \sqrt{ - 24 {}^{2} - 4 \times 9 \times 16} = 0$

$x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a} = \frac{ -( - 24)± \sqrt{0} }{2 \times 9} = \frac{ 24}{18} = \frac{ 4}{3}$

The root is 4/3