Question

Quadratic equation ax2+bx+c =0 have different real roots if :

a) b² - 4ac > 0 b) b² - 4ac = 0 c) b² - 4ac < 0 d) 4ab - c² = 0​

Answer 1

Answer:

The Answer is a)

${b}^{2} - 4ac > 0$

Answer 2

Answer:

a)b²-4ac>0 is the correct answer