Question

quadratic equation class 11​

Answer 1

Answer:

$10 {x}^{ - 2} - 9 - {x}^{ - 4 }{= 0} \\ let \: \: {x}^{ - 2} = y \: \: \implies {x}^{ - 4} = {y}^{2} \\ \\ 10y - 9 - {y}^{2} = 0 \\ {y}^{2} - 9y - y + 9 = 0 \\ (y - 9)(y - 1) = 0 \\ y = 1 \: \: and \: \: 9 \\ \\ \frac{1}{ {x}^{2} } = 1 \: \: and \: \: 9 \\ \\ x= \sqrt{ \frac{1}{1} } \: \: and \: \: \sqrt{ \frac{1}{9} } \\ \\ x = \pm1 \: \: \: and \: \: \pm \frac{1}{3}$