Question

quadratic equation
Fmd the value of k for which the quadratic equation (k + 4)x' + (k+1)x + 1 = 0 has two real
equal roots.

Answer 1

Step-by-step explanation:

given it has two real roots means

discriminant(D) > 0.

and. D=b^2-4ac

here a=k+4 , b=k+1 , c=1

D= (k+1)^2-4(k+1) (1)

D=k^2+1+2k-4k-4

D=k^2-2k-3

then by factorising we get

=k^2-3k+k-3

=k(k-3)+1(k-3)

k=(k+1)(k-3)

k=(-1,3)