Question

quadratic equation please show the solution
r2 - 10r = -17

Answer 1

Answer:

${r}^{2} - 10r = - 17 \\ \\ {r}^{2} - 10r + 17 = 0$

THEIRS NO SOLUTION FOR THE EQUATION...

BECAUSE 17 IS A PRIME NUMBER....

Answer 2

Answer number 2:—

b^2-4ac

(-10)^2-4×1×17

100-68

32>0

we know

b^2-4ac>0

therefore, the given quadratic equation has two real roots .

By completing the square

r^2-10r=-17

r^2-10r+100/4=-17+100/4

(r-10/2)^2=(-68+100)/4

(r-10/2)^2=8

r-10/2=+-2root2 [by square root both side]

r=+-2root2+10/2

therefore r = 5+2root2 or r = 5- 2root2