Question

quadratic equation solve 2xsquare+4x-3=0

Answer 1

let

2x^2+4x-3=o

comparing with ax^2+bx+c=o

a=2

b=4

c=-3

b^2-4ac=

=4^2-4(-3*2)

=16-4(-6)

=16+24

=40

x=-b-\+underoot b^2-4ac/2a

x=-4-\+underroot 40/2*2

=-4-\+2underroot 10/4

=4(-1-\+1/2 underroot 10/4

=-1-\+1/2 underroot 10

x=-1-1/2 underroot 10

Or

X=-1+1/2 underroot 10