Question

quadratic equation,
$2x {}^{2} + x - 28 = 0 \\ 2y { }^{2} - 23y + 56 = 0$
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Answer 1

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${2x}^{2} + x - 28 = 0$

a = 2 , b = 1 and c = -28.

$2 {y}^{2} - 23y + 56 = 0.$

a = 2 b = -23 and c = 56.

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