Question

quadratic equation whose roots are -2 and -3√2
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Answer 1

Step-by-step explanation:

$\alpha + \beta = - 2 \\ \alpha \beta = - 3 \sqrt{2}$

Required Quadratic Equation

$x {}^{2} - ( \alpha + \beta )x + \alpha \beta \\ x {}^{2} - ( - 2)x + ( - 3 \sqrt{2)} \\ x {}^{2} + 2x - 3 \sqrt{2}$