Question

Quadratic equation:-)
x^2-√2x-4=0
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Answer 1

Answer:

hope it helps....

Step-by-step explanation:

Zeroes are -√2 and 2√2

Answer 2

Answer:

$\: {x}^{2} - \sqrt{2x} - 4 = 0 \\ = > {x}^{2} - 2 \sqrt{2x} - \sqrt{2x} - 4 = 0 \\ = > x(x - 2 \sqrt{2} ) - \sqrt{2} (x - 2 \sqrt{2} ) \\ = > (x - 2 \sqrt{2})(x - \sqrt{2} ) \\ \\ \\ \\( x - 2 \sqrt{2} ) = 0 \\ = > x = 2 \sqrt{2} \\ \\ \\ \\( x - \sqrt{2} ) = 0 \\ = > x = \sqrt{2}$

Hence,the required zeroes / roots are 2√2 and √2.