Question

Quadratic equation x square minus kx + 4 is equals to zero has equal roots find value of k

Answer 1

x²- kx + 4 = 0

If it has equal roots => it is a perfect square
=> x² - kx + 2² = a²
=> k = 4
=> x² - 4x + 2²

Answer 2

$\huge \mathfrak{heya \: mate}$


HERE'S YOUR ANSWER


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${x}^{2} - kx + 4 = 0 \\ \\ \\ since \: it \: has \: equal \: roots$



${b}^{2} - 4ac = 0 \\ \\ = > { (- k)}^{2} - 4 \times 1 \times 4 = 0 \\ \\ = > {k}^{2} - 16 = 0 \\ \\ = > {k}^{2} = 16 \\ \\ = > k \: = \sqrt{16 } \\ \\ = > k = 4\\ \\ \\ \\ \\ \\ \huge \boxed{answer = 4}$
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