Question

quadratic equation x²-20x+100=0​

Answer 1

$Given \: Quadratic \: equation :\\ x^{2}-20x+100=0$

/* Splitting the middle term , we get */

$\implies x^{2} - 10x - 10x + 100 = 0$

$\implies x( x - 10 ) - 10 ( x - 10 ) = 0$

$\implies ( x - 10 )( x - 10 ) = 0$

$\implies x - 10 = 0 \: Or \: x - 10 = 0$

$\implies x = 10 \: Or \: x = 10$

Therefore.,

$\green { 10, 10 \: are \: two \: equal \: roots }\\\green { of \: given \: Quadratic \: equation }$

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Answer 2

Answer:

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