Question

quadratic equation


x2-x-6=0. 6
x2-3x-2x-6=0, -3 -2
┻━┻
+
x(x-3)+2(x-3)
(x+2) (x-3)
x+2=0, x-3=0
x=0-2 x=0+3
x=-2 x=3​

Answer 1

Answer:

$x = 3 \: or \: x = - 2$

Step-by-step explanation:

${x}^{2} - x - 6 = 0$

${x}^{2} - (3 - 2)x - 6 = 0$

${x}^{2} - 3x + 2x - 6 = 0$

$x(x - 3) + 2(x - 3) = 0$

$(x - 3)(x + 2) = 0$

$(x - 3) = 0 \: or \: (x + 2) = 0$

$x = 3 \: or \: x = - 2$

i hope it will help u mate❤❤