Question

★ Quadratic Equations ★

1: An express train takes 1 hour less then a passenger train to travel 132 km between Mysore & Bangalore ( without taking into consideration the time they stop at intermediate stations ). If the average speed of the express train is 11 km/h more than that of the passenger train, find the average speed of the two trains.

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Answer 1

Let us say, the average speed of passenger train = x km/h.

Average speed of express train = (x + 11) km/h

Given,

time taken by the express train to cover 132 km is 1 hour less than the passenger train to cover the same distance.

Therefore,

(132/x) – (132/(x+11)) = 1

132(x+11-x)/(x(x+11)) = 1

132 × 11 /(x(x+11)) = 1

⇒ 132 × 11 = x(x + 11)

⇒ x^2 + 11x – 1452 = 0

⇒ x^2 + 44x -33x -1452 = 0

⇒ x(x + 44) -33(x + 44) = 0

⇒ (x + 44)(x – 33) = 0

⇒ x = – 44, 33

As we know,

Speed cannot be negative.

Therefore,

the speed of the passenger train will be 33 km/h and thus, the speed of the express train will be 33 + 11 = 44 km/h.

Answer 2

Check tne attachment for the Answer

Hope this helps you....