Quadratic Equations ★
1: An express train takes 1 hour less then a passenger train to travel 132 km between Mysore & Bangalore ( without taking into consideration the time they stop at intermediate stations ). If the average speed of the express train is 11 km/h more than that of the passenger train, find the average speed of the two trains.
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Answers
Answer:
Let x km per hour be the average speed of the passenger train, then the average speed of the express train will be (x+11) km per hour.
The time taken by the passenger train is
x
132
hour and the time taken by the express train is
(x+11)
132
hour. So,
x+11
132
=
x
132
+1
x
2
+11x−1452=0
x
2
+44x−33x−1452=0
(x−33)(x+44)=0
x=33,x=−44
The speed cannot be negative, so the speed of the passenger train is 33 km per hour and the speed of the express train is 33+11=44 km per hour.
Hope this helped you!
Answer:
passenger train speed=44km/h
express train speed=55 km/h
Explanation:
let, passenger train speed = x
express train speed = x+11
; time taken by passenger train= 10/x
time taken by express train =10/x+11
now , time taken by passanger train- time taken by express train= 1 hour
::: 132/x - 132/x+11 = 1
::: 1452= x^2+11x
::: x^2-11x-1452=0
::: x=44