Question

quadratic equations
1. (x+1)2=2(x-3)
2.x2-2x=(-2) (3-x)
3.(x-2)(x+1)=(x-1)(x+3)​

Answer 1

3. Solution for the third one the highest degree is not 2 after solving the equation hence the equation is not a quadratic equation

When we solve the equations

1. (X+1)2=2(x-3)

2x+2=2x-6

2x-2x = -6-2

0. = -8

which is not possible. hence the equation (x+1)2=2(x-3) is not a quadratic equation

2.

${x}^{2} - 2x = - 2(3 - x)$

${x}^{2} - 2x = - 2 \times 3 - ( - 2)( - x)$

${x}^{2} - 2x = - 6 - 2x$

${x}^{2} - 2x + 2x + 6 = 0$

${x}^{2} + 6 = 0$

the highest degree of the variable 'x' in this equation. hence this is a quadratic equation