Quadratic Equations 2x²-5x-3=0
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Answered by
1
Answer:
Step-by-step explanation:
Here, we have
⇒ 2x² - 5x + 3 = 0
Dividing equation by 2, we get
⇒ x² - 5/2x + 3/2 = 0
Shifting the constant term on RHS
⇒ x² - 5/2x = - 3/2
Adding (1/2 coefficient of x)² on both sides
⇒ (x - 5/4)² = 25/16 - 3/2
⇒ (x - 5/2)² = 1/16
⇒ x - 5/4 = ± 1/4 or x = 5/4 - 1/4 = 4/4
⇒ x = 3/2, 1
Hence, the roots of the equation 2x² - 5x + 3 = 0 are 3/2 and 1.
Answered by
0
Answer:
Hence zeroes are = 3,-1/2
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