Question

quadratic equations in the form ax²+bx+c=0 write the values of a,b,c (x-2)²=5x-8
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Answer 1

Question:-

${(x - 2)}^{2} = 5x - 8$

Answer:-

${x}^{2} - 4 = 5x - 8$

${x}^{2} - 5x - 4 + 8 = 0$

${x}^{2} - 5x + 4 = 0$

Here, is your required answer.

Hope it helps you dear.......xd

Answer 2

Answer:

a=1 b=-9 c=12

Step-by-step explanation:

(x-2)^=x^2-4x+4=5x-8

then"x^2-4x+4=5x-8

x^2-4x-5x+4+8=0

x^2-9x+12=0

hence a=1"b=-9"c=12Ans